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Marxism-Fennekinism to Programmer [email protected]English • 2 years ago

Our social interaction in a nutshell

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Our social interaction in a nutshell

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Marxism-Fennekinism to Programmer [email protected]English • 2 years ago
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  • dohpaz42
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    20•2 years ago

    Honestly dodged a bullet there when they can’t even get their errors straight. Obviously an undefined variable you and me would be more appropriate. Duh. 👯‍♀️

  • @[email protected]
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    3•2 years ago

    I am the mayor of Bonetown — Population: you and me.

  • @[email protected]
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    5•2 years ago

    Less than three

    …unless 😳

  • @[email protected]
    cake
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    6•2 years ago

    I know my calculus. It says you+me = us

    Stupid AI!

  • @[email protected]
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    29•2 years ago

    “undefinedundefined”

    • Marxism-FennekinismOP
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      13•2 years ago

      [Object object]

      • abclop99
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        2•2 years ago

        [object Object]

  • Rentlar
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    16•2 years ago

    When js is ur bf/gf:

    84

    49

    36

    59

    youme

  • @[email protected]
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    92•2 years ago

    Should have used python. The answer is youme.

    • Square Singer
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      11•2 years ago

      Only if you put “you” and “me” in quotation marks.

      • @[email protected]
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        8•2 years ago

        It’s a variable created when the conversation started.

    • Zagorath
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      31•2 years ago

      Most languages support concatenation of strings using the + operator. The only mainstream languages I can think of that don’t are PHP (which uses “.”) and low-level languages like C & C++.

      • @[email protected]
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        4•2 years ago

        C++ does, but it’s not a very efficient operation. https://en.cppreference.com/w/cpp/string/basic_string/operator%2B

        • Zagorath
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          2•
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          2 years ago

          I ran

          #include 
          #include 
          
          int main()
          {
            std::string name;
            std::cout << "you"+"me";
          }
          

          Using cpp.sh, and got the following error:

          main.cpp:7:21: error: invalid operands to binary expression ('const char[4]' and 'const char[3]')
            std::cout << "you"+"me";
                         ~~~~~^~~~~
          1 error generated.
          

          edit: lemmy seems to be determined to convert my less than characters to their HTML entity codes, but the error is meant to point to the “+” sign.

          • @[email protected]
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            1•2 years ago

            This is because your operands are const char[]. That’s not a std::string.

        • @[email protected]
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          3•2 years ago

          Using the C++ standard library beyond the C backwards compatible parts? What devilry is this‽

        • @[email protected]
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          1•2 years ago

          I think your link has a double encoded % at the end: %25

          The correct link is https://en.cppreference.com/w/cpp/string/basic_string/operator2B

      • VanillaGorilla
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        25•2 years ago

        JavaScript might even concatenate some integers instead of adding them just for shits and giggles.

      • @[email protected]
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        8•2 years ago

        Lua uses ..

      • Rikudou_Sage
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        9•2 years ago

        C++ does as well, doesn’t it? Though I don’t often use std::string, so I’m not sure. But every other string type I worked with had + overloaded.

        • Zagorath
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          2•2 years ago

          I dunno, I’ve never actually worked in C++, but I tried it out online and it didn’t seem to work.

      • @[email protected]
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        12•2 years ago

        R uses paste0() for some reason

    • @[email protected]
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      14•2 years ago

      The answer is NameError: ‘you’ is not defined

    • @[email protected]
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      3•2 years ago

      The answer is false. youme !<3

  • Cyrus Draegur
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    35•
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    2 years ago

    My brain is too mushy to do it myself right now, but I wonder what the result would be if we were to consider the alphabet a base-26 number system and added the numbers that correspond to those letters.

    actually, fuck it lets go

    me (13),(5)

    you (25),(15),(20)

    5 + 20 = 25 (y)

    13 + 15 = 28 (carry)
    28 - 26 = 2 (b)

    25 + (carried) 1 = 26 (z)

    you + me = zby.

    • Ethanol
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      14•2 years ago

      I feel like javascript would actually do this :P

    • @[email protected]
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      5•2 years ago

      Pepsi?

      Extra credit!

    • darcy
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      2•2 years ago

      💞💞💞zby

  • @[email protected]
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    39•
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    2 years ago

    If you are one and I am one then you plus me is love.

    you = 1

    me = 1

    you + me < 3

    • oce 🐆
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      10•2 years ago

      You may try to divide us but we’ll always be as one.

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