No not the curvature. For every one degree off you are of a target at 60 miles away you will miss your target by one mile. So if you were 60 miles from your target and you rotated 365, you would miss it by 5 miles. Hence you could spin 365 and miss it, if you were far enough away.
You mean you could accidentally spin 364.9° or 365.1° instead of 365° exactly and you’d be off by a large amount? Might be dumb but still not getting how a perfect pivot right back to 0°/365° would still miss!
Technically speaking with 365* of rotation if you are far enough away you will be able to walk past microsoft, so this is possible.
Because of the Earth’s curvature you mean?
No not the curvature. For every one degree off you are of a target at 60 miles away you will miss your target by one mile. So if you were 60 miles from your target and you rotated 365, you would miss it by 5 miles. Hence you could spin 365 and miss it, if you were far enough away.
You mean you could accidentally spin 364.9° or 365.1° instead of 365° exactly and you’d be off by a large amount? Might be dumb but still not getting how a perfect pivot right back to 0°/365° would still miss!
Because a perfect circle is 360* not 365 so you would be 5* off perfect thereby miss by 5 miles at 60 miles distance.
God damn I am dumb. Thanks for spelling it out lol!