Cyniez to [email protected] • 1 month agoCan anyone solve this math for me?lemmy.worldimagemessage-square43fedilinkarrow-up1141
arrow-up1141imageCan anyone solve this math for me?lemmy.worldCyniez to [email protected] • 1 month agomessage-square43fedilink
minus-squareRentlarlinkfedilink68•edit-21 month agoNote that the problem states that the outer shape is a quarter circle, information not provided in OP’s question. Knowing it is a quarter circle is important because it allows us to validate that the bottom-right angle is 90 degrees.
minus-square@[email protected]linkfedilinkEnglish2•1 month agobut does it have to be a given, or can we actually prove that it has to be
minus-square@[email protected]linkfedilink17•1 month agoIt has to be given, otherwise there would be infinitely many solutions. You would need some other information to link the line segment X to the rest of the figure.
minus-square@[email protected]linkfedilinkEnglish3•1 month agoI actually came to the comments to see if we had this information! Thanks.
minus-square@[email protected]linkfedilink5•1 month agoThe explanation don’t explain why AE must be a diameter of the circle. What makes that obvious?
minus-square@[email protected]linkfedilink3•1 month agoHow have I had years of math and not seen this? I mean, it’s not super useful for me, but I would have thought I would have seen something like this in pre calculus at least.
minus-square@[email protected]linkfedilink1•1 month agoI teach this to my grade 9 class in Canada. It’s on the curriculum.
minus-square@[email protected]linkfedilink1•1 month agoNice. I have no recollection of seeing this before.
minus-square@[email protected]linkfedilink4•1 month agoThanks. I had the same Q: https://en.m.wikipedia.org/wiki/Thales’s_theorem
minus-square@[email protected]linkfedilinkEnglish1•1 month agoTats so cool! Did you just do that or find it?
X=15
Note that the problem states that the outer shape is a quarter circle, information not provided in OP’s question.
Knowing it is a quarter circle is important because it allows us to validate that the bottom-right angle is 90 degrees.
but does it have to be a given, or can we actually prove that it has to be
It has to be given, otherwise there would be infinitely many solutions.
You would need some other information to link the line segment X to the rest of the figure.
I actually came to the comments to see if we had this information! Thanks.
Wow, that’s cool
The explanation don’t explain why AE must be a diameter of the circle. What makes that obvious?
Thales’ Theorem
How have I had years of math and not seen this? I mean, it’s not super useful for me, but I would have thought I would have seen something like this in pre calculus at least.
Geometry, class six or seven.
I teach this to my grade 9 class in Canada. It’s on the curriculum.
Nice. I have no recollection of seeing this before.
Tbf most Canadian grade 9 teachers skip it.
Thanks. I had the same Q: https://en.m.wikipedia.org/wiki/Thales’s_theorem
Tats so cool! Did you just do that or find it?
Ooh clever