• Eager Eagle
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    101
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    2 years ago

    51 = 3*17

    3*17 = 17 + 17 + 17

    17 + 17 + 17 = (10+7) + (10+7) + (10+7)

    (10+7) + (10+7) + (10+7) = 30 + 21

    30 + 21 = 51

    yup, math checks out

    • @[email protected]
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      2 years ago

      I think you skipped a step:

      1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

      Edit: Ohhhh, math by tens, I totally missed it. In that case, my mind wants to break it down to (10 * 5) + 1, and I’d still totally miss 17 as a possible factor.

      • @[email protected]
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        172 years ago

        You miss a couple os steps too.

        First, lets define the axioms, we’re using Peano’s for this exercise.

        Axiom 1: 0 is a natural number.

        Jump to axiom 6, define the succession function s(n) where s(n) = 0 is false, and for brevity s(0) = 1, s(s(0)) = 2 and so on…

    • BOMBS
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      202 years ago

      51 = 3*17

      3*17 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3

      3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1)

      (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) + (2+1) = 34 + 17

      34 + 17 = 51

      👌

  • @[email protected]
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    152 years ago

    Technically, isn’t everything divisible by any number? You just get remainders and/or fractions in the result?

    I mean, I still didn’t want to know this, but…

    • @[email protected]
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      52 years ago

      By definition to be divisible by a number you have to a have a whole number with no remainder as an answer

    • kadu
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      82 years ago

      isn’t everything divisible by any number?

      Do 5/0

  • kingthrillgore
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    102 years ago

    I used to do this thing where I would figure out if a number was prime or not and it kept me sane. Realizing this isn’t, may have just caused my whole world to fall apart.

    • autokludge
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      122 years ago

      If you skipped checking divisibility by 3 you already messed up.

  • Flying SquidM
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    182 years ago

    Math is hard, so I’m just going to assume that’s true and move on with my day.

      • @[email protected]
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        2 years ago

        This one has always bothered me a bit because …999999 is the same as infinity, so when you’re “proving” this, you’re doing math using infinity as a real number which we all know it’s not.

        • @[email protected]
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          22 years ago

          Yes, you’re right this doesn’t work for real numbers.

          It does however work for 10-adic numbers which are not real numbers. They’re part of a different number system where this is allowed.

        • @[email protected]
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          2 years ago

          You can also prove it a different way if you allow the use of the formula for finding the limit if a geometric series on a non-convergent series.

          Sum(ar^n, n=0, inf) = a/(1-r)

          So,

          …999999

          = 9 + 90 + 900 + 9000…

          = 9x10^0 + 9x10^1 + 9x10^2 + 9x10^3…

          = Sum(9x10^n, n=0, inf)

          = 9/(1-10)

          = -1

  • @[email protected]
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    62 years ago

    I actually really like this. 17 is three less than 20, 20x3 is 60, 3x3 is 9, 51 is 60-9. It just feels nice how it all fits together.

  • @[email protected]
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    2 years ago

    weird how ppl are getting all excited over this. weirder all the random math facts on the comments. and everyone checking with long math as if it might not be lol. I guess I’ll throw a few math facts in?

    17 is a prime number. 3 is a prime number.

    all numbers can be factored down to primes.

    19 is a prime number.

    19*3=57. is that one gross too?

    • @[email protected]
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      2 years ago

      What’s weird is that 17 feels like a small enough number where it seems like we should know intuitively what its multiples are. And it feels like by this point in our lives we should at least know all numbers up to 100 or so that are composite vs prime. But yeah it’s actually not that weird when you consider that the multiplication table usually stops at 12. And also that we really don’t get that much exercise in multiplication in daily life.

  • @[email protected]
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    312 years ago

    Any number where the individual digits add up to a number divisible by ‘3’ is divisible by 3.

    51 = 5+1 = 6, which is divisible by three.

    Try it, you’ll see it always works.

      • @[email protected]
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        72 years ago

        They didn’t teach stuff like this in school, which is silly. This is the kind of thing that a kid would eat up. It’s like they wanted to make sure people hated math.

        • @[email protected]
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          42 years ago

          My experience of maths in high school was being taught a trick or method to solve a really specific type of problem every week. Sometimes the method would build off something we’d learnt the previous week.

          The whole thing was bottom-up learning where you get given piecemeal nuggets of information but never see the big picture. They completely lost me at around the age of 15. I eventually came back to maths later in life after studying formal logic in my philosophy undergrad degree.

    • @[email protected]
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      102 years ago

      There are tricks like that for a lot of numbers. For 7, chop off the last digit, double it and add it to what’s left. Repeat as required. If the result is divisible by 7 then the original number was. eg: 356 -> 35+12=47 not db7. 357 =>35+14 both db7 so we don’t even need to do the add.