Day 2: Red-Nosed Reports

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FAQ

  • @[email protected]
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    5 months ago

    #Rust

    initially, for part two I was trying to ignore a bad pair not a bad value - read the question!

    Only installed Rust on Sunday, day 1 was a mess, today was more controlled. Need to look at some of the rust solutions for std library methods I don’t know about.

    very focussed on getting it to actually compile/work over making it short or nice!

    long!

    `

    pub mod task_2 {

    pub fn task_1(input: &str) -> i32{
        let mut valid_count = 0;
    
        let reports = process_input(input);
    
        for report in reports{
            let valid = is_report_valid(report);
    
            if valid{
                valid_count += 1;
            }
        }
    
        println!("Valid count: {}", valid_count);
        valid_count
    }
    
    pub fn task_2(input: &str) -> i32{
        let mut valid_count = 0;
    
        let reports = process_input(input);
    
        for report in reports{
            let mut valid = is_report_valid(report.clone());
    
            if !valid
            {
                for position_to_delete in 0..report.len()
                {
                    let mut updated_report = report.clone();
                    updated_report.remove(position_to_delete);
                    valid = is_report_valid(updated_report);
    
                    if valid { break; }
                }
            }
    
            if valid{
                valid_count += 1;
            }
        }
    
        println!("Valid count: {}", valid_count);
        valid_count
    }
    
    fn is_report_valid(report:Vec<i32>) -> bool{
        let mut increasing = false;
        let mut decreasing = false;
        let mut valid = true;
    
        for position in 1..report.len(){
            if report[position-1] > report[position]
            {
                decreasing = true;
            }
            else if report[position-1] < report[position]
            {
                increasing = true;
            }
            else
            {
                valid = false;
                break;
            }
    
            if (report[position-1] - report[position]).abs() > 3
            {
                valid = false;
                break;
            }
    
            if increasing && decreasing
            {
                valid = false;
                break;
            }
        }
    
        return valid;
    }
    
    pub fn process_input(input: &str) -> Vec<Vec<i32>>{
        let mut reports: Vec<Vec<i32>> = Vec::new();
        for report_string in input.split("\n"){
            let mut report: Vec<i32> = Vec::new();
            for value in report_string.split_whitespace() {
                report.push(value.parse::<i32>().unwrap());
            }
            reports.push(report);
        }
    
        return reports;
    }
    

    }

    `

  • bugsmith
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    15 months ago

    Elixir

    defmodule Day02 do
      defp part1(reports) do
        reports
        |> Enum.map(fn report ->
          levels =
            report
            |> String.split()
            |> Enum.map(&String.to_integer/1)
    
          cond do
            sequence_is_safe?(levels) ->
              :safe
    
            true ->
              :unsafe
          end
        end)
        |> Enum.count(fn x -> x == :safe end)
      end
    
      defp part2(reports) do
        reports
        |> Enum.map(fn report ->
          levels =
            report
            |> String.split()
            |> Enum.map(&String.to_integer/1)
    
          sequences =
            0..(length(levels) - 1)
            |> Enum.map(fn i ->
              List.delete_at(levels, i)
            end)
    
          cond do
            sequence_is_safe?(levels) ->
              :safe
    
            Enum.any?(sequences, &sequence_is_safe?/1) ->
              :safe
    
            true ->
              :unsafe
          end
        end)
        |> Enum.count(fn x -> x == :safe end)
      end
    
      defp all_gaps_within_max_diff?(numbers) do
        numbers
        |> Enum.chunk_every(2, 1, :discard)
        |> Enum.all?(fn [a, b] -> abs(b - a) <= 3 end)
      end
    
      defp is_strictly_increasing?(numbers) do
        numbers
        |> Enum.chunk_every(2, 1, :discard)
        |> Enum.all?(fn [a, b] -> a < b end)
      end
    
      defp is_strictly_decreasing?(numbers) do
        numbers
        |> Enum.chunk_every(2, 1, :discard)
        |> Enum.all?(fn [a, b] -> a > b end)
      end
    
      defp sequence_is_safe?(numbers) do
        (is_strictly_increasing?(numbers) or
           is_strictly_decreasing?(numbers)) and all_gaps_within_max_diff?(numbers)
      end
    
      def run(data) do
        reports = data |> String.split("\n", trim: true)
        p1 = part1(reports)
        p2 = part2(reports)
        IO.puts(p1)
        IO.puts(p2)
      end
    end
    
    data = File.read!("input.in")
    Day02.run(data)
    
  • @[email protected]
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    5 months ago

    Factor

    : get-input ( -- reports )
      "vocab:aoc-2024/02/input.txt" utf8 file-lines
      [ split-words [ string>number ] map ] map ;
    
    : slanted? ( report -- ? )
      { [ [ > ] monotonic? ] [ [ < ] monotonic? ] } || ;
    
    : gradual? ( report -- ? )
      [ - abs 1 3 between? ] monotonic? ;
    
    : safe? ( report -- ? )
      { [ slanted? ] [ gradual? ] } && ;
    
    : part1 ( -- n )
      get-input [ safe? ] count ;
    
    : fuzzy-reports ( report -- reports )
      dup length <iota> [ remove-nth-of ] with map ;
    
    : tolerable? ( report -- ? )
      { [ safe? ] [ fuzzy-reports [ safe? ] any? ] } || ;
    
    : part2 ( -- n )
      get-input [ tolerable? ] count ;
    
    • the_beber
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      25 months ago

      Quite the interesting language choice. It’s so clean. I love it!

  • @[email protected]
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    5 months ago

    G’MIC solution

    spoiler
    it day2
    crop. 0,0,0,{h#-1-2}
    split. -,{_'\n'}
    foreach { replace_str. " ",";" ({t}) rm.. }
    
    safe_0,safe_1=0
    foreach {
    	({h}) a[-2,-1] y
    	num_of_attempts:=da_size(#-1)+1
    	store temp
    
    	repeat $num_of_attempts {
    
    		$temp
    
    		if $> eval da_remove(#-1,$>-1) fi
    
    		eval "
    			safe=1;
    			i[#-1,1]>i[#-1,0]?(
    				for(p=1,p<da_size(#-1),++p,
    					if(!inrange(i[#-1,p]-i[#-1,p-1],1,3,1,1),safe=0;break(););
    				);
    			):(
    				for(p=1,p<da_size(#-1),++p,
    					if(!inrange(i[#-1,p-1]-i[#-1,p],1,3,1,1),safe=0;break(););
    				);
    			);
    			safe;"
    
    		rm
    
    		if $>
    			if ${} safe_1+=1 break fi
    		else
    			if ${} safe_0,safe_1+=1 break fi
    		fi
    
    	}
    
    }
    
    echo Day" "2:" "${safe_0}" :: "${safe_1}
    
  • the_beber
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    15 months ago

    Kotlin:

    import kotlin.math.abs
    import kotlin.math.sign
    
    data class Report(val levels: List<Int>) {
        fun isSafe(withProblemDampener: Boolean): Boolean {
            var orderSign = 0.0f  // - 1 is descending; +1 is ascending
    
            levels.zipWithNext().forEachIndexed { index, level ->
                val difference = (level.second - level.first).toFloat()
                if (orderSign == 0.0f) orderSign = sign(difference)
                if (sign(difference) != orderSign || abs(difference) !in 1.0..3.0) {
                    // With problem dampener: Drop either element in the pair or the first element from the original list and check if the result is now safe.
                    return if (withProblemDampener) {
                        Report(levels.drop(1)).isSafe(false) || Report(levels.withoutElementAt(index)).isSafe(false) || Report(levels.withoutElementAt(index + 1)).isSafe(false)
                    }  else false
                }
            }
    
            return true
        }
    }
    
    fun main() {
        fun part1(input: List<String>): Int = input.map { Report(it.split(" ").map { it.toInt() }).isSafe(false) }.count { it }
    
        fun part2(input: List<String>): Int = input.map { Report(it.split(" ").map { it.toInt() }).isSafe(true) }.count { it }
    
        // Or read a large test input from the `src/Day01_test.txt` file:
        val testInput = readInput("Day02_test")
        check(part1(testInput) == 2)
        check(part2(testInput) == 4)
    
        // Read the input from the `src/Day01.txt` file.
        val input = readInput("Day02")
        part1(input).println()
        part2(input).println()
    }
    
    

    The Report#isSafe method essentially solves both parts.

    I’ve had a bit of a trip up in part 2:

    I initially only checked, if the report was safe, if either elements in the pair were to be removed. But in the edge case, that the first pair has different monotonic behaviour than the rest, the issue would only be detected by the second pair with indices (2, 3), whilst removing the first element in the list would yield a safe report.

  • @[email protected]
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    15 months ago

    Uiua

    Took me a bit longer to get this one but still quite simple overall.
    Spent quite some time on getting to know the try and assert operators better.

    Run with example input here

    # Get the indices matching the ascending/
    # descending criteria
    CheckAsc ← ≡°□⍚(⍣(⊸⍤.≍⍆.)⍣(⊸⍤.≍⇌⍆.)0)
    # Get the indices matching the distance criteria
    CheckDist ← ≡°□⍚(⍣(⊸⍤.≠1∈:0)0×⊓≥≤1,3⌵⧈-)
    Split     ← ⊙(▽≠1)▽,,
    
    PartOne ← (
      &rs ∞ &fo "input-2.txt"
      ⊜(□⊜⋕≠@ .)≠@\n.
      CheckAsc.
      ▽
      CheckDist
      ⧻⊚
    )
    
    PartTwo ← (
      &rs ∞ &fo "input-2.txt"
      ⊜(□⊜⋕≠@ .)≠@\n.
      CheckAsc.
      Split
      CheckDist.
      Split
      ⊙(⊂)
      ⧻
      :
      ⍚(≡(▽:°⊟)⍜¤⊞⊟:≠1⊞=.⇡⧻.)
      ≡(⧻⊚CheckDist▽CheckAsc.°□)
      +⧻◴⊚
    )
    
    &p "Day 2:"
    &pf "Part 1: "
    &p PartOne
    &pf "Part 2: "
    &p PartTwo
    
  • @[email protected]
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    15 months ago

    C#

    using MathNet.Numerics.LinearAlgebra;
    public class Day02 : Solver
    {
      private ImmutableList<Vector<Double>> data;
    
      public void Presolve(string input)
      {
        data = input.Trim().Split("\n")
            .Select(
                line => Vector<Double>.Build.DenseOfEnumerable(line.Split(' ').Select(double.Parse))
            ).ToImmutableList();
      }
    
      private bool IsReportSafe(Vector<Double> report) {
        Vector<Double> delta = report.SubVector(1, report.Count - 1)
            .Subtract(report.SubVector(0, report.Count - 1));
        return (delta.ForAll(x => x > 0) || delta.ForAll(x => x < 0))
            && Vector<Double>.Abs(delta).Max() <= 3;
      }
    
      private bool IsDampenedReportSafe(Vector<Double> report) {
        for (Double i = 0; i < report.Count; ++i) {
          var dampened = Vector<Double>.Build.DenseOfEnumerable(
                report.EnumerateIndexed()
                    .Where(item => item.Item1 != i)
                    .Select(item => item.Item2));
          if (IsReportSafe(dampened)) return true;
        }
        return false;
      }
    
      public string SolveFirst() => data.Where(IsReportSafe).Count().ToString();
    
      public string SolveSecond() => data.Where(IsDampenedReportSafe).Count().ToString();
    }
    
  • @[email protected]
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    5 months ago

    Uiua

    Uiua is still developing very quickly, and this code uses the experimental tuples function, hence the initial directive.

    Try it Live!

    # Experimental!
    "7 6 4 2 1\n1 2 7 8 9\n9 7 6 2 1\n1 3 2 4 5\n8 6 4 4 1\n1 3 6 7 9"
    ⊜(⊜⋕⊸≠@\s)⊸≠@\n # Partition at \n, then at space, parse ints.
    
    IsSorted ← +⊃(≍⇌⍆.|≍⍆.)        # Compare with sorted array.
    IsSmall  ← /××⊃(>0|<4)⌵↘¯1-↻1. # Copy offset by 1, check diffs.
    IsSafe   ← ×⊃IsSmall IsSorted  # Safe if Small steps and Ordered.
    IsSafer  ← ±/+≡IsSafe ⧅<-1⧻.   # Choose 4 from 5, check again.
    
    &p/+≡IsSafe .            # Part1 : Is each row safe?
    &p/+≡(±+⊃IsSafe IsSafer) # Part2 : Is it safe or safer?
    
    • @[email protected]
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      75 months ago

      How do you write this, not conceptually but physically. Do you have a char picker open at all times?

      • @[email protected]
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        45 months ago

        Haha, you can do it that way, in fact the online Uiua Pad editor has all the operators listed along the top.

        But all the operators have ascii names, so you can type e.g. IsSmall = reduce mul mul fork(>0|<4) abs drop neg 1 - rot 1 dup and the formatter will reduce that to IsSmall ← /××⊃(>0|<4)⌵↘¯1-↻1. whenever you save or execute code.

        That works in the Pad, and you can enable similar functionality in other editors.

        • @[email protected]
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          45 months ago

          I like to assume people using array programming languages just have a crystal ball that they use to call upon magic runes on the screen

    • @[email protected]
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      35 months ago

      This looks so alien! Does it work with the full set? The comment says 5, choose 4, but I guess it’s written as n, choose n-1?

      • @[email protected]
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        15 months ago

        Yes, it should do. I do run the solutions against the live data, but sometimes tweak the solutions afterwards, so can’t always guarantee them :-). I left the comment as 5 choose 4 as it felt clearer in the context of the test data.

        It does still feel very alien at times, but I do love being able to think about how to adopt a more arrays-based approach to solving these problems.

  • @[email protected]
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    35 months ago

    TypeScript

    Solution
    import { AdventOfCodeSolutionFunction } from "./solutions";
    
    
    /**
     * this function evaluates the 
     * @param levels a list to check
     * @returns -1 if there is no errors, or the index of where there's an unsafe event
     */
    export function EvaluateLineSafe(levels: Array<number>) {
        // this loop is the checking every number in the line
        let isIncreasing: boolean | null = null;
        for (let levelIndex = 1; levelIndex < levels.length; levelIndex++) {
            const prevLevel = levels[levelIndex - 1]; // previous
            const level = levels[levelIndex]; // current
            const diff = level - prevLevel; // difference
            const absDiff = Math.abs(diff); // absolute difference
    
            // check if increasing too much or not at all
            if (absDiff == 0 || absDiff > 3)
                return levelIndex; // go to the next report
    
            // set increasing if needed
            if (isIncreasing === null) {
                isIncreasing = diff > 0;
                continue; // compare the next numbers
            }
    
            //  check if increasing then decreasing 
            if (!(isIncreasing && diff > 0 || !isIncreasing && diff < 0))
                return levelIndex; // go to the next report
        }
    
        return -1;
    }
    
    
    export const solution_2: AdventOfCodeSolutionFunction = (input) => {
        const reports = input.split("\n");
    
        let safe = 0;
        let safe_damp = 0;
    
        // this loop is for every line
        main: for (let i = 0; i < reports.length; i++) {
            const report = reports[i].trim();
            if (!report)
                continue; // report is empty
    
            const levels = report.split(" ").map((v) => Number(v));
    
            const evaluation = EvaluateLineSafe(levels);
            if(evaluation == -1) {
                safe++;
                continue;
            }
            
            // search around where it failed
            for (let offset = evaluation - 2; offset <= evaluation + 2; offset++) {
                // delete an evaluation in accordance to the offset
                let newLevels = [...levels];
                newLevels.splice(offset, 1);
                const newEval = EvaluateLineSafe(newLevels);
                if(newEval == -1) {
                    safe_damp++;
                    continue main;
                }
            }
        }
    
        return `Part 1: ${safe} Part 2: ${safe + safe_damp}`;
    }
    

    God, I really wish my solutions weren’t so convoluted. Also, this is an O(N^3) solution…

        • @[email protected]
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          25 months ago

          It’s not as simple as that. You can have 20 nested for loops with complexity of O(1) if all of them only ever finish one iteration.

          Or you can have one for loop that iterates 2^N times.

          • @[email protected]
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            15 months ago

            What do you think my complexity is?

            I think it could be maybe O(n^2) because the other for loop which tries elements around the first error will only execute a constant of 5 times in the worst case? I’m unsure.

            • @[email protected]
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              35 months ago

              It really depends on what your parameter n is. If the only relevant size is the number of records (let’s say that is n), then this solution takes time in O(n), because it loops over records only once at a time. This ignores the length of records by considering it constant.

              If we also consider the maximum length of records (let’s call it m), then your solution, and most others I’ve seen in this thread, has a time complexity in O(n * m^2) for part 2.

            • @[email protected]
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              35 months ago

              It’s O(n).

              If you look at each of the levels of all reports, you will access it a constant number of times: at most twice in each call to EvaluateLineSafe, and you will call EvaluateLineSafe at most six times for each report.

  • @[email protected]
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    15 months ago

    Elixir

    defmodule AdventOfCode.Solution.Year2024.Day02 do
      use AdventOfCode.Solution.SharedParse
    
      @impl true
      def parse(input) do
        for line <- String.split(input, "\n", trim: true),
            do: String.split(line) |> Enum.map(&String.to_integer/1)
      end
    
      def part1(input) do
        Enum.count(input, &is_safe(&1, false))
      end
    
      def part2(input) do
        Enum.count(input, &(is_safe(&1, true) or is_safe(tl(&1), false)))
      end
    
      def is_safe([a, b, c | rest], can_fix) do
        cond do
          (b - a) * (c - b) > 0 and abs(b - a) in 1..3 and abs(c - b) in 1..3 ->
            is_safe([b, c | rest], can_fix)
    
          can_fix ->
            is_safe([a, c | rest], false) or is_safe([a, b | rest], false)
    
          true ->
            false
        end
      end
    
      def is_safe(_, _), do: true
    end
    
  • Zarlin
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    25 months ago

    Nim

    import strutils, times, sequtils, sugar
    
    # check if level transition in record is safe
    proc isSafe*(sign:bool, d:int): bool =
      sign == (d>0) and d.abs in 1..3;
    
    #check if record is valid
    proc validate*(record:seq[int]): bool =
      let sign = record[0] > record[1];
      return (0..record.len-2).allIt(isSafe(sign, record[it] - record[it+1]))
    
    # check if record is valid as-is
    # or if removing any item makes the record valid
    proc validate2*(record:seq[int]): bool =
      return record.validate or (0..<record.len).anyIt(record.dup(delete(it)).validate)
    
    proc solve*(input:string): array[2,int] =
      let lines = input.readFile.strip.splitLines;
      let records = lines.mapIt(it.splitWhitespace.map(parseInt));
      result[0] = records.countIt(it.validate);
      result[1] = records.countIt(it.validate2);
    

    I got stuck on part 2 trying to check everything inside a single loop, which kept getting more ugly. So then I switched to just deleting one item at a time and re-checking the record.

    Reworked it after first finding the solution to compress the code a bit, though the range iterators don’t really help with readability.

    I did learn about the sugar import, which I used to make the sequence duplication more compact: record.dup(delete(it).

    • janAkali
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      2
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      5 months ago

      Cool to see another solution in Nim here =)

      (0..<record.len).anyIt(record.dup(delete(it)).validate)

      That’s smart. I haven’t thought of using iterators to loop over indexes (except in a for loop).

      I got stuck on part 2 trying to check everything inside a single loop, which kept getting more ugly.

      Yeah I’ve thought of simple ways to do this and found none. And looking at the input - it’s too easy to bruteforce, especially in compiled lang like Nim.

  • @[email protected]
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    15 months ago

    R (R-Wasm)

    input = file('input2024day2.txt',open='r')
    lines = readLines(input)
    library(stringr)
    safe = 0
    safe2 = 0
    for (ln in lines){
      vals = as.numeric(unlist(str_split(ln,' ')))
      diffs = diff(vals)
      cond1 = min(diffs) > 0 || max(diffs) < 0
      cond2 = max(abs(diffs)) < 4
      if (cond1 && cond2){
        safe = safe + 1
      }
      else { #Problem Dampener
        dampen = FALSE
        for (omit in -1:-length(vals)){
          diffs = diff(vals[omit])
          cond1 = min(diffs) > 0 || max(diffs) < 0
          cond2 = max(abs(diffs)) < 4
          if (cond1 && cond2){
            dampen = TRUE
          }
        }
        if (dampen){
          safe2 = safe2 + 1}
      }
    }
    print (safe) #Part 1
    print (safe + safe2) #Part 2
    
  • @[email protected]
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    35 months ago

    J

    There is probably a way to write this more point-free. You can definitely see here the friction involved in the way J wants to regard lists as arrays: short rows of the input matrix are zero padded, so you have to snip off the padding before you process each row, and that means you can’t lift some of the operations back up to the parent matrix because it will re-introduce the padding as it reshapes the result; this accounts for a lot of the "1 everywhere (you can interpret v"1 as “force the verb v to operate on rank 1 subarrays of the argument”).

    data_file_name =: '2.data'
    data =: > 0 ". each cutopen toJ fread data_file_name
    
    NB. {. take, i. index of; this removes trailing zeros
    remove_padding =: {.~ i.&amp;0
    
    NB. }. behead, }: curtail; this computes successive differences
    diff =: }. - }:
    
    NB. a b in_range y == a &lt;: y &lt;: b
    in_range =: 4 : '(((0 { x) &amp; &lt;:) * (&lt;: &amp; (1 { x))) y'
    
    NB. a row is safe if either all successive differences are in [1..3] or all in [_3.._1]
    NB. +. or
    ranges =: 2 2 $ 1 3 _3 _1
    row_safe =: (+./"1) @: (*/"1) @: (ranges &amp; (in_range"1 _)) @: diff @: remove_padding
    
    result1 =: +/ safe"1 data
    
    NB. x delete y is y without the xth element
    delete =: 4 : '(x {. y) , ((>: x) }. y)'"0 _
    modified_row =: 3 : 'y , (i.#y) delete y'
    
    modified_row_safe =: 3 : '+./"1 row_safe"1 modified_row"1 y'
    result2 =: +/ modified_row_safe data
    
  • @[email protected]
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    15 months ago
    def is_safe(report: list[int]) -> bool:
        global removed
        acceptable_range = [_ for _ in range(-3,4) if _ != 0]
        diffs = []
        if any([report.count(x) > 2 for x in report]):
            return False
        for i, num in enumerate(report[:-1]):
            cur = num
            next = report[i+1]
            difference = cur - next
            diffs.append(difference)
            if difference not in acceptable_range:
                return False
            if len(diffs) > 1:
                if diffs[-1] * diffs[-2] <= 0:
                    return False
        return True
    
    with open('input') as reports:
        list_of_reports = reports.readlines()[:-1]
    
    
    count = 0
    
    failed_first_pass = []
    failed_twice = []
    
    for reportsub in list_of_reports:
        levels = [int(l) for l in reportsub.split()]
        original = levels.copy()
        if is_safe(levels):
            safe = True
            count += 1
        else:
            failed_first_pass.append(levels)
    
    for report in failed_first_pass:
        print(report)
        working_copy = report.copy()
        for i in range(len(report)):
            safe = False
            working_copy.pop(i)
            print("checking", working_copy)
            if is_safe(working_copy):
                count += 1
                safe = True
                break
            else:
                working_copy = report.copy()
    
    print(count)
    
    • @[email protected]
      link
      fedilink
      15 months ago

      this took me so fucking long and in the end i just went for brute force anyway. there are still remnants of some of previous, overly complicated, failed attempts, like the hideous global removed. In the end, I realized I was fucking up by using remove() instead of pop(), it was causing cases with duplicates where the removal of one would yield a safe result to count as unsafe.

  • Deebster
    link
    fedilink
    2
    edit-2
    5 months ago

    I forgot that this started yesterday, so I’m already behind. I quite like my solution for part one, but part two will have to wait edit: part 2 was a lot simpler than I thought after a night’s sleep.

    Rust

    use color_eyre::eyre;
    use std::{fs, num, str::FromStr};
    
    #[derive(Debug, PartialEq, Eq)]
    struct Report(Vec<isize>);
    
    impl FromStr for Report {
        type Err = num::ParseIntError;
    
        fn from_str(s: &str) -> Result<Self, Self::Err> {
            let v: Result<Vec<isize>, _> = s
                .split_whitespace()
                .map(|num| num.parse::<isize>())
                .collect();
            Ok(Report(v?))
        }
    }
    
    impl Report {
        fn is_safe(&self) -> bool {
            let ascending = self.0[1] > self.0[0];
            let (low, high) = if ascending { (1, 3) } else { (-3, -1) };
            self.0.windows(2).all(|w| {
                let a = w[0];
                let b = w[1];
                b >= a + low && b <= a + high
            })
        }
    
        fn is_dampsafe(&self) -> bool {
            if self.is_safe() {
                return true;
            }
            for i in 0..self.0.len() {
                let damped = {
                    let mut v = self.0.clone();
                    v.remove(i);
                    Self(v)
                };
                if damped.is_safe() {
                    return true;
                }
            }
            false
        }
    }
    
    fn main() -> eyre::Result<()> {
        color_eyre::install()?;
    
        let part1 = part1("d02/input.txt")?;
        let part2 = part2("d02/input.txt")?;
        println!("Part 1: {part1}\nPart 2: {part2}");
        Ok(())
    }
    
    fn part1(filepath: &str) -> eyre::Result<isize> {
        let mut num_safe = 0;
        for l in fs::read_to_string(filepath)?.lines() {
            if Report::from_str(l)?.is_safe() {
                num_safe += 1;
            }
        }
        Ok(num_safe)
    }
    
    fn part2(filepath: &str) -> eyre::Result<isize> {
        let mut num_safe = 0;
        for l in fs::read_to_string(filepath)?.lines() {
            if Report::from_str(l)?.is_dampsafe() {
                num_safe += 1;
            }
        }
        Ok(num_safe)
    }
    
    Tests
    #[cfg(test)]
    mod tests {
        use super::*;
    
        #[test]
        fn sample_part1() {
            assert_eq!(part1("test.txt").unwrap(), 2);
        }
    
        #[test]
        fn sample_part2() {
            assert_eq!(part2("test.txt").unwrap(), 4);
        }
    }