Day 8: Resonant Collinearity

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

  • the_beber
    link
    fedilink
    17 months ago

    Kotlin

    A bit late to the party, but here’s my solution. I don’t know, if you even need to search for the smallest integer vector in the same direction in part 2, but I did it anyway.

    Code:
    import kotlin.math.abs
    import kotlin.math.pow
    
    fun main() {
        fun part1(input: List<String>): Int {
            val inputMap = Day08Map(input)
            return inputMap.isoFrequencyNodeVectorsByLocations
                .flatMap { (location, vectors) ->
                    vectors.map { (2.0 scaleVec it) + location }
                }
                .toSet()
                .count { inputMap.isInGrid(it) }
        }
    
        fun part2(input: List<String>): Int {
            val inputMap = Day08Map(input)
            return buildSet {
                inputMap.isoFrequencyNodeVectorsByLocations.forEach { (location, vectors) ->
                    vectors.forEach { vector ->
                        var i = 0.0
                        val scaledDownVector = smallestIntegerVectorInSameDirection2D(vector)
                        while (inputMap.isInGrid(location + (i scaleVec scaledDownVector))) {
                            add(location + (i scaleVec scaledDownVector))
                            i++
                        }
                    }
                }
            }.count()
        }
    
        val testInput = readInput("Day08_test")
        check(part1(testInput) == 14)
        check(part2(testInput) == 34)
    
        val input = readInput("Day08")
        part1(input).println()
        part2(input).println()
    }
    
    tailrec fun gcdEuclid(a: Int, b: Int): Int =
        if (b == 0) a
        else if (a == 0) b
        else if (a > b) gcdEuclid(a - b, b)
        else gcdEuclid(a, b - a)
    
    fun smallestIntegerVectorInSameDirection2D(vec: VecNReal): VecNReal {
        assert(vec.dimension == 2)  // Only works in two dimensions.
        assert(vec == vec.roundComponents())  // Only works on integer vectors.
    
        return (gcdEuclid(abs(vec[0].toInt()), abs(vec[1].toInt())).toDouble().pow(-1) scaleVec vec).roundComponents()
    }
    
    class Day08Map(input: List<String>): Grid2D<Char>(input.reversed().map { it.toList() }) {
        init {
            transpose()
        }
    
        val isoFrequencyNodesLocations = asIterable().toSet().filter { it != '.' }.map { frequency -> asIterable().indicesWhere { frequency == it } }
        val isoFrequencyNodeVectorsByLocations = buildMap {
            isoFrequencyNodesLocations.forEach { isoFrequencyLocationList ->
                isoFrequencyLocationList.mapIndexed { index, nodeLocation ->
                    this[VecNReal(nodeLocation)] = isoFrequencyLocationList
                        .slice((0 until index) + ((index + 1)..isoFrequencyLocationList.lastIndex))
                        .map { VecNReal(it) - VecNReal(nodeLocation) }
                }
            }
        }
    }
    
    
  • @[email protected]OPM
    link
    fedilink
    8
    edit-2
    7 months ago

    Rust

    For the first time, I can post my solution, because I actually solved it on the day :D Probably not the cleanest or optimal solution, but it does solve the problem.

    Very long, looking forward to someone solving it in 5 lines of unicode :D

    #[cfg(test)]
    mod tests {
    
        fn get_frequences(input: &str) -> Vec<char> {
            let mut freq = vec![];
            for char in input.chars() {
                if char == '.' {
                    continue;
                }
                if !freq.contains(&char) {
                    freq.push(char);
                }
            }
            freq
        }
    
        fn find_antennas(board: &Vec<Vec<char>>, freq: char) -> Vec<(isize, isize)> {
            let mut antennas = vec![];
            for (i, line) in board.iter().enumerate() {
                for (j, char) in line.iter().enumerate() {
                    if *char == freq {
                        antennas.push((i as isize, j as isize));
                    }
                }
            }
            antennas
        }
    
        fn calc_antinodes(first: &(isize, isize), second: &(isize, isize)) -> Vec<(isize, isize)> {
            let deltax = second.0 - first.0;
            let deltay = second.1 - first.1;
    
            if deltax == 0 && deltay == 0 {
                return vec![];
            }
    
            vec![
                (first.0 - deltax, first.1 - deltay),
                (second.0 + deltax, second.1 + deltay),
            ]
        }
    
        #[test]
        fn test_calc_antinodes() {
            let expected = vec![(0, -1), (0, 2)];
            let actual = calc_antinodes(&(0, 0), &(0, 1));
            for i in &expected {
                assert!(actual.contains(i));
            }
            let actual = calc_antinodes(&(0, 1), &(0, 0));
            for i in &expected {
                assert!(actual.contains(i));
            }
        }
    
        fn calc_all_antinodes(board: &Vec<Vec<char>>, freq: char) -> Vec<(isize, isize)> {
            let antennas = find_antennas(&board, freq);
    
            let mut antinodes = vec![];
    
            for (i, first) in antennas.iter().enumerate() {
                for second in antennas[i..].iter() {
                    antinodes.extend(calc_antinodes(first, second));
                }
            }
    
            antinodes
        }
    
        fn prune_nodes(
            nodes: &Vec<(isize, isize)>,
            height: isize,
            width: isize,
        ) -> Vec<(isize, isize)> {
            let mut pruned = vec![];
            for node in nodes {
                if pruned.contains(node) {
                    continue;
                }
                if node.0 < 0 || node.0 >= height {
                    continue;
                }
                if node.1 < 0 || node.1 >= width {
                    continue;
                }
                pruned.push(node.clone());
            }
            pruned
        }
    
        fn print_board(board: &Vec<Vec<char>>, pruned: &Vec<(isize, isize)>) {
            for (i, line) in board.iter().enumerate() {
                for (j, char) in line.iter().enumerate() {
                    if pruned.contains(&(i as isize, j as isize)) {
                        print!("#");
                    } else {
                        print!("{char}");
                    }
                }
                println!();
            }
        }
    
        #[test]
        fn day8_part1_test() {
            let input: String = std::fs::read_to_string("src/input/day_8.txt").unwrap();
    
            let frequencies = get_frequences(&input);
    
            let board = input
                .trim()
                .split('\n')
                .map(|line| line.chars().collect::<Vec<char>>())
                .collect::<Vec<Vec<char>>>();
    
            let mut all_nodes = vec![];
            for freq in frequencies {
                let nodes = calc_all_antinodes(&board, freq);
                all_nodes.extend(nodes);
            }
    
            let height = board.len() as isize;
            let width = board[0].len() as isize;
    
            let pruned = prune_nodes(&all_nodes, height, width);
    
            println!("{:?}", pruned);
    
            print_board(&board, &pruned);
    
            println!("{}", pruned.len());
    
            // 14 in test
        }
    
        fn calc_antinodes2(first: &(isize, isize), second: &(isize, isize)) -> Vec<(isize, isize)> {
            let deltax = second.0 - first.0;
            let deltay = second.1 - first.1;
    
            if deltax == 0 && deltay == 0 {
                return vec![];
            }
            let mut nodes = vec![];
            for n in 0..50 {
                nodes.push((first.0 - deltax * n, first.1 - deltay * n));
                nodes.push((second.0 + deltax * n, second.1 + deltay * n));
            }
    
            nodes
        }
    
        fn calc_all_antinodes2(board: &Vec<Vec<char>>, freq: char) -> Vec<(isize, isize)> {
            let antennas = find_antennas(&board, freq);
    
            let mut antinodes = vec![];
    
            for (i, first) in antennas.iter().enumerate() {
                for second in antennas[i..].iter() {
                    antinodes.extend(calc_antinodes2(first, second));
                }
            }
    
            antinodes
        }
    
        #[test]
        fn day8_part2_test() {
            let input: String = std::fs::read_to_string("src/input/day_8.txt").unwrap();
    
            let frequencies = get_frequences(&input);
    
            let board = input
                .trim()
                .split('\n')
                .map(|line| line.chars().collect::<Vec<char>>())
                .collect::<Vec<Vec<char>>>();
    
            let mut all_nodes = vec![];
            for freq in frequencies {
                let nodes = calc_all_antinodes2(&board, freq);
                all_nodes.extend(nodes);
            }
    
            let height = board.len() as isize;
            let width = board[0].len() as isize;
    
            let pruned = prune_nodes(&all_nodes, height, width);
    
            println!("{:?}", pruned);
    
            print_board(&board, &pruned);
    
            println!("{}", pruned.len());
        }
    }
    
  • @[email protected]
    link
    fedilink
    English
    5
    edit-2
    7 months ago

    Haskell

    I overslept 26 minutes (AoC starts at 06:00 here) which upsets me more than it should.
    I thought this one was going to be hard on performance or memory but it was surprisingly easy.

    import Control.Arrow hiding (first, second)
    import Data.Bifunctor
    
    import Data.Array.Unboxed (UArray)
    
    import qualified Data.List as List
    import qualified Data.Set as Set
    import qualified Data.Array.Unboxed as Array
    
    parse :: String -> UArray (Int, Int) Char
    parse s = Array.listArray ((1, 1), (n, m)) . filter (/= '\n') $ s :: UArray (Int, Int) Char
    
            where
                    n = takeWhile   (/= '\n') >>> length $ s
                    m = List.filter (== '\n') >>> length >>> pred $ s
    
    groupSnd:: Eq b => (a, b) -> (a', b) -> Bool
    groupSnd = curry (uncurry (==) <<< snd *** snd)
    
    cartesianProduct xs ys = [(x, y) | x <- xs, y <- ys]
    
    calculateAntitone ((y1, x1), (y2, x2)) = (y1 + dy, x1 + dx)
            where
                    dy = y1 - y2
                    dx = x1 - x2
    
    antennaCombinations = Array.assocs
            >>> List.filter (snd >>> (/= '.'))
            >>> List.sortOn snd
            >>> List.groupBy groupSnd
            >>> map (map fst)
            >>> map (\ xs -> cartesianProduct xs xs)
            >>> map (filter (uncurry (/=)))
    
    part1 a = antennaCombinations
            >>> List.concatMap (map calculateAntitone)
            >>> List.filter (Array.inRange (Array.bounds a))
            >>> Set.fromList
            >>> Set.size
            $ a
    
    calculateAntitones ((y1, x1), (y2, x2)) = iterate (bimap (+dy) (+dx)) (y1, x1)
            where
                    dy = y1 - y2
                    dx = x1 - x2
    
    part2 a = antennaCombinations
            >>> List.map (map calculateAntitones)
            >>> List.concatMap (List.concatMap (takeWhile (Array.inRange (Array.bounds a))))
            >>> Set.fromList
            >>> Set.size
            $ a
    
    main = getContents
            >>= print
            . (part1 &&& part2)
            . parse
    
    • Amy
      link
      fedilink
      27 months ago

      D’oh. Computing antinodes in a single direction and permuting pairs is a much neater approach that what I did!

  • @[email protected]
    link
    fedilink
    17 months ago

    TypeScript

    I was a little confuzzled with this one, but I managed to get it. :) Happy to know that I managed to reuse more of my code from previous days. I should write something to handle Vectors. It was sad to write my own basic, non-reusable thing.

    Solution
    import { AdventOfCodeSolutionFunction } from "./solutions";
    
    // imported code:
    export const check_coords = (grid: Array<Array<any>>, x: number, y: number) => {
        return y >= grid.length ||
            y < 0 ||
            x >= grid[y].length ||
            x < 0
    }
    
    export const makeGridFromMultilineString =
        (input: string) => input.split("\n").map(st => st.trim()).map(v => v.split(""));
    
    export const MakeEmptyGenericArray = <T>(length: number, fn: (index: number) => T) => {
        const newArray = [];
        let i = 0;
        while (i++ < length)
            newArray.push(fn(i));
    
        return newArray;
    }
    
    export const MakeEmptyArray = (length: number) => MakeEmptyGenericArray(length, () => 0);
    export const MakeEmpty2DArray = (x: number, y: number) => MakeEmptyArray(y).map(() => MakeEmptyArray(x));
    
    // solution code
    type v2 = [x: number, y: number];
    
    const Sub = (x1: number, y1: number, x2: number, y2: number): v2 => {
        return [x1 - x2, y1 - y2];
    }
    
    const Add = (x1: number, y1: number, x2: number, y2: number): v2 => {
        return [x1 + x2, y1 + y2];
    }
    
    export const solution_8: AdventOfCodeSolutionFunction = (input) => {
        const grid = makeGridFromMultilineString(input);
        const nodes = new Map<string, Array<v2>>();
        const nodeKinds: Array<string> = [];
        const singleAntinodeLocations = MakeEmpty2DArray(grid.length, grid[0].length);
        const resonantAntinodeLocations = MakeEmpty2DArray(grid.length, grid[0].length);
    
        // find all the nodes
        grid.forEach((row, y) => row.forEach((item, x) => {
            if (item == ".")
                return;
    
            if (nodes.has(item))
                nodes.get(item)!.push([x, y]);
    
            else {
                nodes.set(item, [[x, y]]);
                nodeKinds.push(item);
            }
        }));
    
        nodeKinds.forEach((nodeKind) => {
            const nodesOfKind = nodes.get(nodeKind)!;
            for (let bunn = 0; bunn < nodesOfKind.length; bunn++) {
                const first = nodesOfKind[bunn];
                for (let tort = bunn + 1; tort < nodesOfKind.length; tort++) {
                    // find antinode
                    const second = nodesOfKind[tort];
                    const diff = Sub(...first, ...second);
                    const [x1, y1] = Add(...first, ...diff);
                    const [x2, y2] = Sub(...second, ...diff);
    
                    if(!check_coords(singleAntinodeLocations, x1, y1)) singleAntinodeLocations[y1][x1]++;
                    if(!check_coords(singleAntinodeLocations, x2, y2)) singleAntinodeLocations[y2][x2]++;
    
                    // find all resonances
                    // starting
                    resonantAntinodeLocations[first[1]][first[0]]++;
                    resonantAntinodeLocations[second[1]][second[0]]++;
    
                    // go forward
                    let newFirst = [x1, y1] as v2;
                    while(!check_coords(resonantAntinodeLocations, ...newFirst)) {
                        let [x, y] = newFirst;
                        resonantAntinodeLocations[y][x]++;
                        newFirst = Add(...newFirst, ...diff);
                    }
    
                    // go back
                    newFirst = [x2, y2] as v2;
                    while(!check_coords(resonantAntinodeLocations, ...newFirst)) {
                        let [x, y] = newFirst;
                        resonantAntinodeLocations[y][x]++;
                        newFirst = Sub(...newFirst, ...diff);
                    }
                }
            }
        });
    
        const antinodeCount = (prev: number, curr: Array<number>) => prev + curr.reduce((prev, curr) => prev + (curr > 0 ? 1 : 0), 0);
        const part_1 = singleAntinodeLocations.reduce<number>(antinodeCount, 0);
        const part_2 = resonantAntinodeLocations.reduce<number>(antinodeCount, 0);
    
        return {
            part_1, //390
            part_2, //1246
        }
    }
    
    

    Loops on loops on loops on loops…

  • @[email protected]
    link
    fedilink
    17 months ago

    Rust

    Proper Point and Vector types made this pretty simple, part 2 was just a tiny change (basically while instead of if), but left with a lot of copy-pasted code.

    Solution
    use euclid::default::*;
    
    const N_ANTENNAS: usize = (b'z' - b'0') as usize + 1;
    // For each frequency (from b'0' to b'z') the list of antenna positions
    type Antennas = Box<[Vec<Point2D<i32>>]>;
    
    fn parse(input: String) -> (Antennas, Rect<i32>) {
        let mut antennas = vec![Vec::new(); N_ANTENNAS].into_boxed_slice();
        let mut width = 0;
        let mut height = 0;
        for (y, l) in input.lines().enumerate() {
            height = y + 1;
            if width == 0 {
                width = l.len()
            } else {
                assert!(width == l.len())
            }
            for (x, b) in l.bytes().enumerate().filter(|(_, b)| *b != b'.') {
                antennas[(b - b'0') as usize].push(Point2D::new(x, y).to_i32())
            }
        }
        let bounds = Rect::new(Point2D::origin(), Size2D::new(width, height).to_i32());
        (antennas, bounds)
    }
    
    fn part1(input: String) {
        let (antennas, bounds) = parse(input);
        let mut antinodes = vec![vec![false; bounds.width() as usize]; bounds.height() as usize];
        for list in antennas.iter().filter(|l| !l.is_empty()) {
            for (i, &a) in list.iter().enumerate().skip(1) {
                for &b in list.iter().take(i) {
                    let diff = b - a;
                    let ax = a - diff;
                    if bounds.contains(ax) {
                        antinodes[ax.y as usize][ax.x as usize] = true;
                    }
                    let bx = b + diff;
                    if bounds.contains(bx) {
                        antinodes[bx.y as usize][bx.x as usize] = true;
                    }
                }
            }
        }
        let sum = antinodes
            .iter()
            .map(|row| row.iter().map(|b| u32::from(*b)).sum::<u32>())
            .sum::<u32>();
        println!("{sum}");
    }
    
    fn part2(input: String) {
        let (antennas, bounds) = parse(input);
        let mut antinodes = vec![vec![false; bounds.width() as usize]; bounds.height() as usize];
        for list in antennas.iter().filter(|l| !l.is_empty()) {
            for (i, &a) in list.iter().enumerate().skip(1) {
                for &b in list.iter().take(i) {
                    let diff = b - a;
                    // Start at antenna a, keep going until hitting bounds
                    let mut ax = a;
                    while bounds.contains(ax) {
                        antinodes[ax.y as usize][ax.x as usize] = true;
                        ax -= diff;
                    }
                    let mut bx = b;
                    while bounds.contains(bx) {
                        antinodes[bx.y as usize][bx.x as usize] = true;
                        bx += diff;
                    }
                }
            }
        }
        let sum = antinodes
            .iter()
            .map(|row| row.iter().map(|b| u32::from(*b)).sum::<u32>())
            .sum::<u32>();
        println!("{sum}");
    }
    
    util::aoc_main!();
    

    also on github

      • @[email protected]
        link
        fedilink
        17 months ago

        I try to use Vecs instead of HashSets and maps whenever the key domain is reasonably small (just the grid in this case), simply because in the end direct memory access is a lot faster than always hashing values.

        But looking at this case again, it is certainly a lot easier to have just antinodes.len() at the end instead of counting all true values. This datastructure is also not really performance-critical, so a HashSet is probably the cleaner choice here.

  • @[email protected]
    link
    fedilink
    47 months ago

    Uiua

    Adapting the part one solution for part two took me longer than part one did today, but I didn’t want to change much anymore.

    I even got scolded by the interpreter to split the evaluating line onto multiple ones because it got too long.
    Can’t say it’s pretty but it does it’s job ^^’

    Run with example input here

    PartOne ← (
      &rs ∞ &fo "input-8.txt"
      ⟜(▽¬∈".\n".◴)
      ⊜∘≠@\n.
      :¤⟜(:¤-1△)
      ≡(□⊚⌕)
      ◴/◇⊂⍚(≡(-:⟜-°⊟)⧅≠2)
      ⧻▽¬:⊙(/+⍉+)⟜⊓><,0
    )
    
    PartTwo ← (
      &rs ∞ &fo "input-8.txt"
      ⟜(▽¬∈".\n".◴⟜¤
        ▽:⟜≡(>1⧻⊚⌕)
      )
      ⊜∘≠@\n.
      :¤⟜(:¤-1△)
      ≡(□⊚⌕)
      ⊸⍚(
        ⧅≠2⊙¤
        ≡(:¤⟜-°⊟
          ⍢(⊙⊂⟜-⊙⊸⊢
          | ⋅(=0/++⊓><,0⊢))
          □⊙◌◌
        )
      )
      ◴/◇⊂/◇⊂
      ⧻▽¬:⊙(/+⍉+)⟜⊓><,0
    )
    
    &p "Day 8:"
    &pf "Part 1: "
    &p PartOne
    &pf "Part 2: "
    &p PartTwo
    
  • @[email protected]
    link
    fedilink
    English
    17 months ago

    Rust

    use std::collections::{HashMap, HashSet};
    
    use crate::solver::DaySolver;
    use crate::grid::{Coordinate, Grid};
    
    fn add_distance(coordinate: Coordinate, distance: (i64, i64)) -> Option<Coordinate> {
        coordinate.try_add(distance)
    }
    
    fn sub_distance(coordinate: Coordinate, distance: (i64, i64)) -> Option<Coordinate> {
        coordinate.try_sub(distance)
    }
    
    fn part2_possible_antinodes<F>(
        grid: &Grid<Option<char>>,
        coordinate: Coordinate,
        distance: (i64, i64),
        op: F,
        mut accumulator: Vec<Coordinate>
    ) -> Vec<Coordinate>
    where F: Fn(Coordinate, (i64, i64)) -> Option<Coordinate> {
        match op(coordinate, distance).filter(|c| grid.get(*c).is_some()) {
            None => accumulator,
            Some(next_coord) => {
                accumulator.push(next_coord);
                part2_possible_antinodes(grid, next_coord, distance, op, accumulator)
            }
        }
    }
    
    trait Pairable<T> {
        fn pairs(&self) -> Vec<(&T, &T)>;
    }
    
    impl<T> Pairable<T> for HashSet<T> {
        fn pairs(&self) -> Vec<(&T, &T)> {
            let v: Vec<&T> = self.iter().collect();
    
            let mut p = vec![];
    
            for i in 0..v.len() {
                let thing1 = v[i];
    
                for thing2 in &v[i+1..] {
                    p.push((thing1, *thing2));
                }
            }
    
            p
        }
    }
    
    fn parse_input(input: String) -> (Grid<Option<char>>, HashMap<char, HashSet<Coordinate>>) {
        let g: Grid<Option<char>> =
            input.lines()
            .map(|line| line.chars()
                 .map(|c| if c == '.' {
                     None
                 } else {
                     Some(c)
                 }).collect::<Vec<Option<char>>>()
            )
            .collect::<Vec<Vec<Option<char>>>>()
            .into();
    
        let mut freq_to_coords: HashMap<char, HashSet<Coordinate>> = HashMap::new();
    
        for (coord, freq_opt) in g.iter() {
            match freq_opt {
                None => (),
                Some(freq) => {
                    freq_to_coords.entry(*freq)
                        .and_modify(|coords| {
                            coords.insert(coord);
                        })
                        .or_insert(HashSet::from([coord]));
                }
            }
        }
    
        (g, freq_to_coords)
    }
    
    pub struct Day08Solver;
    
    impl DaySolver for Day08Solver {
        fn part1(&self, input: String) -> usize {
            let (g, freq_to_coords) = parse_input(input);
    
            let mut antinodes: HashSet<Coordinate> = HashSet::new();
    
            for (_, coords) in freq_to_coords {
                // println!("Freq = {}", freq);
                for (c1, c2) in coords.pairs() {
                    let distance = c1.xy_distance_to(c2);
                    let possible_antinodes: Vec<Coordinate> = [c1.try_sub(distance), c2.try_add(distance)].into_iter()
                        .flat_map(|co| co.filter(|c| g.get(*c).is_some()))
                        .collect();
    
                    // println!("Pair = ({},{}), antinodes = {:?}", c1, c2, possible_antinodes);
    
                    for antinode in possible_antinodes {
                        antinodes.insert(antinode);
                    }
                }
            }
    
            antinodes.len()
        }
    
        fn part2(&self, input: String) -> usize {
            let (g, freq_to_coords) = parse_input(input);
    
            let mut antinodes: HashSet<Coordinate> = HashSet::new();
    
            for (freq, coords) in freq_to_coords {
                println!("Freq = {}", freq);
                for (c1, c2) in coords.pairs() {
                    let distance = c1.xy_distance_to(c2);
    
                    let possible_antinodes: Vec<Coordinate> = [
                        part2_possible_antinodes(&g, *c1, distance, add_distance, vec![*c1]),
                        part2_possible_antinodes(&g, *c1, distance, sub_distance, vec![*c1]),
                        part2_possible_antinodes(&g, *c2, distance, add_distance, vec![*c2]),
                        part2_possible_antinodes(&g, *c2, distance, sub_distance, vec![*c2]),
                    ].into_iter().flatten().collect();
    
                    println!("Pair = ({},{}), antinodes = {:?}", c1, c2, possible_antinodes);
    
                    for antinode in possible_antinodes {
                        antinodes.insert(antinode);
                    }
                }
            }
    
            antinodes.len()
        }
    }
    

    https://gitlab.com/bricka/advent-of-code-2024-rust/-/blob/main/src/days/day08.rs?ref_type=heads

  • @[email protected]
    link
    fedilink
    English
    17 months ago

    Rust

    Pretty happy with my solution today. I took my time today as it was a bit of a slow day and did it in Rust instead of python. Having proper Vec2 types is very nice.

    Tap for spoiler
    use std::{collections::HashMap, error::Error, io::Read};
    
    use glam::{IVec2, Vec2};
    
    fn permutations_of_size_two(antennas: &[Vec2]) -> Vec<[&Vec2; 2]> {
        let mut permutations = vec![];
        for (i, antenna) in antennas.iter().enumerate() {
            for j in 0..antennas.len() {
                if i == j {
                    continue;
                }
                permutations.push([antenna, &antennas[j]])
            }
        }
        permutations
    }
    
    fn main() -> Result<(), Box<dyn Error>> {
        let mut input = String::new();
        std::io::stdin().read_to_string(&mut input)?;
    
        let height = input.lines().count() as i32;
        let width = input.lines().next().unwrap().len() as i32;
    
        let antenna_positions = input
            .lines()
            .enumerate()
            .flat_map(|(y, l)| 
                l.chars().enumerate().map(move |(x, c)| (Vec2::new(x as f32, y as f32), c))
            )
            .filter(|(_v, c)| *c != '.')
            .fold(HashMap::new(), |mut acc: HashMap<char, Vec<_>> , current| {
                acc.entry(current.1).or_default().push(current.0);
                acc
            });
    
        let mut antinodes = vec![];
        for (_c, antennas) in antenna_positions {
            let perms = permutations_of_size_two(&antennas);
            for [first, second] in perms {
                let mut i = 1.;
                loop {
                    let antinode = (first + (second-first) * i).round();
                    if (0..height).contains(&(antinode.x as i32)) &&
                        (0..width).contains(&(antinode.y as i32)) {
                            antinodes.push(antinode);
                    } else {
                        break;
                    }
                    i += 1.;
                }
            }
        }
    
        let mut antinode_count = 0;
        let map = input
            .lines()
            .enumerate()
            .map(|(y, l)| 
                l.chars().enumerate().map(|(x, c)| {
                    if antinodes.contains(&Vec2::new(x as f32, y as f32)) {
                        println!("({x},{y})");
                        antinode_count += 1;
                        return '#';
                    }
                    c
                }).collect::<String>()
            )
            .collect::<Vec<_>>()
            .join("\n");
    
        println!("{map}");
        println!("{antinode_count}");
    
        Ok(())
    }
    
  • @[email protected]
    link
    fedilink
    2
    edit-2
    7 months ago

    Lisp

    Could probably just write points right to the results instead of to an intermediate list, but it runs instantly, so my motivation to do so was low.

    Code
    (defun p1-process-line (line)
       (to-symbols line 'advt2024-d8))
      
    (defun count-results (results)
      (loop for i from 0 below (array-total-size results)
            count (row-major-aref results i)))
    
    (defun place-annode (pos results)
      (let ((x (first pos)) (y (second pos)))
        (when (in-map results x y) 
          (setf (aref results y x) t))))
    
    (defun create-annodes-p1 (x1 y1 x2 y2)
      (let ((delta-x (- x2 x1)) (delta-y (- y2 y1)))
        (list (list (- x1 delta-x) (- y1 delta-y)) (list (+ x2 delta-x) (+ y2 delta-y)))))
    
    (defun place-annodes (positions results create-annodes)
      (when positions
         (loop with a = (car positions)
               with x1 = (first a)
               with y1 = (second a)
               for b in (cdr positions)
               for ans = (funcall create-annodes x1 y1 (first b) (second b))
               do (dolist (a ans) (place-annode a results)))
         (place-annodes (cdr positions) results create-annodes)))
    
    (defun place-all-annodes (xmits map &optional (create-annodes #'create-annodes-p1))
      (let ((results (make-array (array-dimensions map) :element-type 'boolean :initial-element nil)))
        (loop for k being the hash-key of xmits
              do (place-annodes (gethash k xmits) results create-annodes))
        results))
    
    (defun find-transmitters (map)
      "look throught the map and record where the transmitters are in a hash map"
      (let ((h (make-hash-table)))
        (destructuring-bind (rows cols) (array-dimensions map)
          (loop for j from 0 below rows
                do (loop for i from 0 below cols
                         for v = (aref map j i)
                         unless (eql v '|.|)
                           do (push (list i j) (gethash v h))
                         )))
        h))
    
    (defun run-p1 (file) 
      (let* ((map (list-to-2d-array (read-file file #'p1-process-line))))
        (count-results (place-all-annodes (find-transmitters map) map))
        ))
    
    (defun create-annodes-2 (x1 y1 x2 y2 map)
      (destructuring-bind (rows cols) (array-dimensions map)
        (let* ((m (/ (- y2 y1) (- x2 x1) ))
               (b (- y2 (* m x2))))
          (loop for x from 0 below cols
                for y = (+ b (* x m))
                for r = (nth-value 1 (floor y))
                when (and (= r 0) (>= y 0) (< y rows))
                  collect (list x y)))))
    
    (defun run-p2 (file) 
      (let* ((map (list-to-2d-array (read-file file #'p1-process-line))))
        (count-results (place-all-annodes (find-transmitters map) map
                                          (lambda (x1 y1 x2 y2)
                                            (create-annodes-2 x1 y1 x2 y2 map))))))
    
    
  • TunaCowboy
    link
    fedilink
    2
    edit-2
    7 months ago

    python

    solution
    import aoc
    
    def setup():
        lines = aoc.get_lines(8, stripped=True)
        ll = len(lines)
        fm = {f: [(x, y) for y, r in enumerate(lines)
                  for x, z in enumerate(r) if z == f]
              for f in {z for r in lines for z in r if z != '.'}}
        return ll, fm
    
    def fa(fm, ll, rh=False):
        ans = set()
        for cd in fm.values():
            l = len(cd)
            for i in range(l):
                x1, y1 = cd[i]
                for j in range(i + 1, l):
                    x2, y2 = cd[j]
                    dx, dy = x2 - x1, y2 - y1
                    if rh:
                        for k in range(-ll, ll):
                            x, y = x1 + k * dx, y1 + k * dy
                            if 0 <= x < ll and 0 <= y < ll:
                                ans.add((x, y))
                    else:
                        x3, y3, x4, y4 = x1 - dx, y1 - dy, x2 + dx, y2 + dy
                        if 0 <= x3 < ll and 0 <= y3 < ll:
                            ans.add((x3, y3))
                        if 0 <= x4 < ll and 0 <= y4 < ll:
                            ans.add((x4, y4))
        return len(ans)
    
    def one():
        ll, fm = setup()
        print(fa(fm, ll))
    
    def two():
        ll, fm = setup()
        print(fa(fm, ll, rh=True))
    
    one()
    two()
    
  • @[email protected]
    link
    fedilink
    17 months ago

    J

    J really doesn’t have hashes! Or anything like hashes! And it’s really annoying after a while!

    What it does have is automatic internal optimization via hashing of the “index of” operation m i. n where m is a fixed list (the object being searched) and n is the query, which can vary. But as soon as you update m the hash table is thrown away. And you still have to choose some kind of numeric key, or store a list of boxed pairs where the first coordinate is the key – effectively this is an old-style Lisp association list, but with extra steps because you have to use boxing to defeat J’s automatic array concatenation and reshaping. If you want non-cubical shapes (J calls these “ragged arrays”), or heterogeneous lists, you end up writing u &amp;.> a lot – this means “unbox, apply u then rebox”. J arrays are required to be rectangular and homogeneous, but a boxed anything is a single atom just like a number is.

    It’s just a really bad choice of language if you want data structures other than essentially-cubical arrays. On the other hand, once you beat the list manipulation primitives into producing your 1970s Lisp data structure of choice, the rest of the program is as nice as it usually is.

    data_file_name =: '8.data'
    grid =: ,. > cutopen fread data_file_name
    'rsize csize' =: $ grid
    inbounds =: monad : '(*/ y >: 0 0) * (*/ y &lt; rsize, csize)'
    antenna_types =: (#~ (~: &amp; '.')) ~. , grid
    NB. list_antennas gives a list of boxed matrices of shape 2 n_k in cell k, where
    NB. n_k is the number of antennas of type k and the rows are coordinates of that type
    list_antennas =: monad define
       antenna_locs =. (# antenna_types) $ a:
       for_r. i. rsize do.
          for_c. i. csize do.
             cell =. y {~ &lt;(r, c)
             if. '.' ~: cell do.
                at =. antenna_types i. cell
                antenna_locs =. ((&lt;(r, c)) ,&amp;.> at { antenna_locs) at} antenna_locs
             end.
          end.
       end.
       NB. _2 ]\ l reshapes l into length 2 rows without finding its length ahead of time
       (_2 &amp; (]\))&amp;.> antenna_locs
    )
    NB. a1 pair_antinodes a2 gives the two antinodes from that pair
    pair_antinodes =: dyad : '(#~ inbounds"1) ((2 * x) - y) ,: (2 * y) - x'
    NB. if u is a symmetric dyad expecting rank 1 arguments, u on_pairs is a monad
    NB. expecting a list of rank 1 arguments, and yields the concatenation of x u y
    NB. where (x, y) is drawn from the (unordered) pairs of elements of the argument
    NB. see page_pairs in 5.ijs for a non-point-free version of pair enumeration
    on_pairs =: adverb define
       ; @: (&lt; @: u/"2) @: ({~ (; @: (&lt; @: (,~"0 i.)"0) @: i. @: #))
    )
    NB. antinodes antennas gives a list (may contain duplicates) of all the antinodes from
    NB. that set of antennas
    antinodes =: pair_antinodes on_pairs
    NB. on_antennas concatenates and uniquifies result lists from all antennas
    on_antennas =: adverb define
       ~. @: ; @: (u &amp;.>) @: list_antennas
    )
    result1 =: # antinodes on_antennas grid
    
    NB. a1 res_antinodes a2 gives the list of antinodes from that pair with resonance
    res_antinodes =: dyad define
       step =. (% +./) x - y
       NB. lazy: max_steps doesn't take location of x into account
       max_steps =. &lt;. (rsize % 1 >. | 0 { step) &lt;. (csize % 1 >. 1 { step)
       (#~ inbounds"1) x +"1 step *"1 0 i: max_steps
    )
    result2 =: # res_antinodes on_pairs on_antennas grid
    
  • @[email protected]
    link
    fedilink
    English
    17 months ago

    Raku

    Solution
    sub MAIN($input) {
        my $file = open $input;
        my @map = $file.slurp.lines>>.comb>>.List.List;
        my %freqs;
        for 0..^@map.elems -> $row {
            for 0..^@map[0].elems -> $col {
                if @map[$row; $col] ne "." {
                    my $freq = @map[$row; $col];
                    %freqs{$freq} = [] if %freqs{$freq}:!exists;
                    %freqs{$freq}.push(($row, $col));
                }
            }
        }
        my %antinodes is SetHash;
        for %freqs.kv -> $freq, @locations {
            for (0..^@locations.elems) X (0..^@locations.elems) -> ($loc1, $loc2) {
                next if $loc1 == $loc2;
                my @base = @locations[$loc1].List;
                my @vector = @locations[$loc2].List Z- @base;
                my @antinode1 = @base Z+ @vector.map(* * 2);
                %antinodes{@antinode1.List.raku}++ if point-is-in-map(@map, @antinode1);
                my @antinode2 = @base Z+ @vector.map(* * -1);
                %antinodes{@antinode2.List.raku}++ if point-is-in-map(@map, @antinode2);
            }
        }
        my $part1-solution = %antinodes.elems;
        say "part 1: $part1-solution";
    
    
        my %antinodes2 is SetHash;
        for %freqs.kv -> $freq, @locations {
            for (0..^@locations.elems) X (0..^@locations.elems) -> ($loc1, $loc2) {
                next if $loc1 == $loc2;
                my @base = @locations[$loc1].List;
                my @vector = @locations[$loc2].List Z- @base;
                # make integer unit-ish vector
                for 2..@vector[0] -> $divisor {
                    if @vector[0] %% $divisor and @vector[1] %% $divisor {
                        @vector[0] = @vector[0] div $divisor;
                        @vector[1] = @vector[1] div $divisor;
                    }
                }
                for 0..max(@map.elems, @map[0].elems) -> $length {
                    my @antinode = @base Z+ @vector.map(* * $length);
                    if point-is-in-map(@map, @antinode) {
                        %antinodes2{@antinode.List.raku}++ 
                    } else {
                        last
                    }
                }
                for 1..max(@map.elems, @map[0].elems) -> $length {
                    my @antinode = @base Z+ @vector.map(* * -$length);
                    if point-is-in-map(@map, @antinode) {
                        %antinodes2{@antinode.List.raku}++ 
                    } else {
                        last
                    }
                }
            }
        }
        my $part2-solution = %antinodes2.elems;
        say "part 2: $part2-solution";
    }
    
    sub point-is-in-map(@map, @point) {
        return False if !(0 <= @point[0] < @map.elems);
        return False if !(0 <= @point[1] < @map[0].elems);
        return True;
    }
    
  • @[email protected]
    link
    fedilink
    47 months ago

    C#

    public class Day08 : Solver
    {
      private ImmutableArray<string> data;
      private int width, height;
    
      public void Presolve(string input) {
        data = input.Trim().Split("\n").ToImmutableArray();
        width = data[0].Length;
        height = data.Length;
      }
    
      public string SolveFirst() {
        Dictionary<char, List<(int, int)>> antennae = [];
        HashSet<(int, int)> antinodes = [];
        for (int i = 0; i < width; i++) {
          for (int j = 0; j < height; j++) {
            if ('.' == data[j][i]) continue;
            antennae.TryAdd(data[j][i], []);
            foreach (var (oi, oj) in antennae[data[j][i]]) {
              int di = i - oi;
              int dj = j - oj;
              int ai = i + di;
              int aj = j + dj;
              if (ai >= 0 && aj >= 0 && ai < width && aj < height) {
                antinodes.Add((ai, aj));
              }
              ai = oi - di;
              aj = oj - dj;
              if (ai >= 0 && aj >= 0 && ai < width && aj < height) {
                antinodes.Add((ai, aj));
              }
            }
            antennae[data[j][i]].Add((i, j));
          }
        }
        return antinodes.Count.ToString();
      }
    
      public string SolveSecond() {
        Dictionary<char, List<(int, int)>> antennae = [];
        HashSet<(int, int)> antinodes = [];
        for (int i = 0; i < width; i++) {
          for (int j = 0; j < height; j++) {
            if ('.' == data[j][i]) continue;
            antennae.TryAdd(data[j][i], []);
            foreach (var (oi, oj) in antennae[data[j][i]]) {
              int di = i - oi;
              int dj = j - oj;
              for (int ai = i, aj = j;
                   ai >= 0 && aj >= 0 && ai < width && aj < height; 
                   ai += di, aj +=dj) {
                antinodes.Add((ai, aj));
              }
              for (int ai = oi, aj = oj;
                   ai >= 0 && aj >= 0 && ai < width && aj < height; 
                   ai -= di, aj -=dj) {
                antinodes.Add((ai, aj));
              }
            }
            antennae[data[j][i]].Add((i, j));
          }
        }
        return antinodes.Count.ToString();
      }
    }
    
  • Amy
    link
    fedilink
    47 months ago

    Haskell

    Not a very pretty solution today, I’m afraid.

    import Control.Arrow
    import Control.Monad
    import Data.Biapplicative
    import Data.Ix
    import Data.Map (Map)
    import Data.Map qualified as Map
    import Data.Set qualified as Set
    
    type Coords = (Int, Int)
    
    readInput :: String -> Map Coords Char
    readInput s =
      Map.fromAscList
        [ ((i, j), c)
          | (i, l) <- zip [0 ..] (lines s),
            (j, c) <- zip [0 ..] l
        ]
    
    (.+.), (.-.) :: Coords -> Coords -> Coords
    (.+.) = join biliftA2 (+)
    (.-.) = join biliftA2 (-)
    
    part1, part2 :: (Coords -> Bool) -> (Coords, Coords) -> [Coords]
    part1 valid (p1, p2) =
      let s = p2 .-. p1
       in filter valid [p1 .-. s, p2 .+. s]
    part2 valid (p1, p2) =
      let (si, sj) = p2 .-. p1
          d = gcd si sj
          s = (si `div` d, sj `div` d)
       in takeWhile valid (iterate (.+. s) p1)
            ++ takeWhile valid (drop 1 $ iterate (.-. s) p2)
    
    pairs (x : xs) = map (x,) xs ++ pairs xs
    pairs _ = []
    
    main = do
      input <- readInput <$> readFile "input08"
      let antennas = Map.filter (/= '.') input
          antennaGroups =
            Map.foldrWithKey
              (\p c m -> Map.insertWith (++) c [p] m)
              Map.empty
              antennas
          valid =
            inRange
              . (Set.findMin &&& Set.findMax)
              $ Map.keysSet input
          antiNodes model =
            Set.fromList
              . concatMap (concatMap (model valid) . pairs)
              $ antennaGroups
      print . Set.size $ antiNodes part1
      print . Set.size $ antiNodes part2
    
    • @[email protected]
      link
      fedilink
      2
      edit-2
      7 months ago

      Whaaat? It is possible to declare mutliple signatures on one line? 🤯
      Does that function (.+.) add tuples/coordinates?

      • Amy
        link
        fedilink
        27 months ago

        Yup, that’s right! The function monad is a bit of a mind-bender, but (join f) x == f x x is a useful thing to remember.

        • @[email protected]
          link
          fedilink
          27 months ago

          This is so cool, it’s going to replace the lambda in my function pipeline for calculating pairs.

          • Amy
            link
            fedilink
            17 months ago

            BTW, for more in-depth vector stuff I usually use the Linear package.

  • @[email protected]
    link
    fedilink
    37 months ago

    Dart

    This really does feel like a weekend break this year, maybe Eric and co have begun to realise that family time is more precious than work time :-)

    import 'dart:math';
    import 'package:more/more.dart';
    
    solve(List<String> lines, int min, int max) {
      var map = ListMultimap<String, Point<int>>();
      for (var r in lines.indices()) {
        for (var ci in lines[r].split('').indexed()) {
          if (ci.value != '.') map[ci.value].add(Point(ci.index, r));
        }
      }
      var anti = <Point<int>>{};
      for (var k in map.keys) {
        for (var p in map[k].combinations(2, repetitions: false)) {
          var diff = p.last - p.first;
          for (var m in min.to(max)) {
            anti.addAll([p.first - diff * m, p.last + diff * m]);
          }
        }
      }
    
      return anti.count((e) =>
          e.x.between(0, lines.first.length - 1) &&
          e.y.between(0, lines.length - 1));
    }
    
    part1(List<String> lines) => solve(lines, 1, 2);
    
    part2(List<String> lines) => solve(lines, 0, 50);
    
    • janAkali
      link
      fedilink
      English
      4
      edit-2
      7 months ago

      maybe Eric and co have begun to realise that family time is more precious than work time

      Last year the difficulty was fluctuating from 0 to 100 each day.
      This year all problems so far are suspiciously easy. Maybe the second half of the month will be extra hard?