The Picard ManeuverM to Lemmy [email protected] • 6 months agoThe grand prizelemmy.worldimagemessage-square125fedilinkarrow-up1930
arrow-up1930imageThe grand prizelemmy.worldThe Picard ManeuverM to Lemmy [email protected] • 6 months agomessage-square125fedilink
minus-square@[email protected]linkfedilink3•edit-26 months agoThat is… surprisingly little. Are you sure?
minus-square@[email protected]linkfedilink1•6 months agoBy weight probably, for it to be a perfectly symmetrical cube would likely cost you double that.
minus-square@[email protected]linkfedilink2•6 months agoI mean, I can only estimate it’s size from the person standing next to it. From there I can use that estimate to get the volume of the cube, then the weight, then look up the cost by weight right now and apply the average. So it would be somewhere around 1mm by weight.
That is… surprisingly little. Are you sure?
By weight probably, for it to be a perfectly symmetrical cube would likely cost you double that.
I mean, I can only estimate it’s size from the person standing next to it. From there I can use that estimate to get the volume of the cube, then the weight, then look up the cost by weight right now and apply the average.
So it would be somewhere around 1mm by weight.