• I Cast Fist
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    148 months ago

    We should test this again, but with a fridge and someone inside it for the nuclear blast. I bet that would work out great

  • @Zwiebel@feddit.org
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    998 months ago

    There is one detail wrong in the first post; that is not the lids speed but rather it’s minimum speed.

    • @Klear@sh.itjust.works
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      178 months ago

      Unfortunately they got almost everything else wrong though. Mainly - the cover actually almost certainly just vaporiserd.

    • @Reddfugee42@lemmy.world
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      748 months ago

      Notice, children, how the common apostrophe from lid’s migrated all the way to its.

      Isn’t nature amazing?

    • @buddascrayon@lemmy.world
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      8 months ago

      The cover obtained all of its energy from the blast, it can only go slower than its initial speed unless acted upon by another force.

      • @TheSlad@sh.itjust.works
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        178 months ago

        No no, because they only had one frame of it moving, they can only calculate and upper and lower bound on it’s speed. The number given was the lower bound is what theyre saying.

    • Victor
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      28 months ago

      That’s assuming it crossed the image straight from edge to edge, though.

  • @MonkderVierte@lemmy.ml
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    8 months ago

    Nope, it would just have bursted due to thermal schock and pressure. Escape velocity, what are you dreaming, is the lid made of tungsten?

    • @IrritableOcelot@beehaw.org
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      27 months ago

      Hypersonic heating is really weird. We only have data going to about mach 17 (the HTV-2 was the fastest solidly atmospheric vehicle I found) but as we go from subsonic, to supersonic, to hypersonic regimes air becomes pretty much incompressible, and forms a really solid shockwave in front of a fast-moving object. Air is a pretty good thermal insulator, so for very fast, blunt objects they actually heat much slower than you might expect.

      Tl;Dr it absolutely vaporized, but it likely lasted longer than you might expect.

    • @logos@sh.itjust.works
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      7 months ago

      This is the origin apparently.

      RRB: “My calculations are irrelevant on this point. They are only valid in speaking of the shock reflection.” Ogle: “How fast did it go?” RRB: “Those numbers are meaningless. I have only a vacuum above the cap. No air, no gravity, no real material strengths in the iron cap. Effectively the cap is just loose, traveling through meaningless space.” Ogle: And how fast is it going?" This last question was more of a shout. Bill liked to have a direct answer to each one of his questions. RRB: “Six times the escape velocity from the earth.”

  • linuxgator
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    98 months ago

    The foundry that made that manhole cover has some great potential advertising claims.

  • @IrritableOcelot@beehaw.org
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    8 months ago

    One thing that no one ever talks about with this is the massive air resistance on it going Mach 164 through the atmosphere would incur (albeit for a very brief period)…I bet that would knock 25-50 kmph off it easily.

  • Radioactive Butthole
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    7 months ago

    Most likely it just evaporated, or disintegrated or something, but I think its pretty unlikely it survived that absolutely bonkers acceleration.

  • @DaddleDew@lemmy.world
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    1348 months ago

    This reminds me of that quote from Mass Effect:

    “This, recruits, is a 20-kilo ferrous slug. Feel the weight! Every five seconds, the main gun of an Everest-class Dreadnought accelerates one to 1.3 percent of light speed. It impacts with the force of a 38-kiloton bomb. That is three times the yield of the city buster dropped on Hiroshima back on Earth. That means: Sir Isaac Newton is the deadliest son-of-a-bitch in space! (…) I dare to assume you ignorant jackasses know that space is empty! Once you fire this hunk of metal, it keeps going 'till it hits something! That can be a ship, or the planet behind that ship. It might go off into deep space and hit somebody else in ten thousand years. If you pull the trigger on this, you are ruining someone’s day, somewhere and sometime!”

  • @Professorozone@lemmy.world
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    668 months ago

    Ummm, not sure where they got these numbers from but Earth’s escape velocity is not 7000mph and escaping the sun’s gravitational pull (leaving the solar system from Earth) is not 30,000mph. Respectively the numbers are approximately 25,000mph and 94,000mph. You’re welcome.

    • @merc@sh.itjust.works
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      37 months ago

      That’s 11.2 km/s and 42.1 km/s.

      Also, even if the manhole cover was going at above 12 km/s the trajectory has to be right for that to result in orbit. Most paths it would take would result in it going up and then coming back down again. Similarly, if somehow it did manage more than 50 km/s and wasn’t destroyed in the atmosphere, it might have the velocity to escape the sun’s gravity, but probably wouldn’t be on the right path to do it. Most likely it would fall into the sun.

      So, assuming the 125,000 mph (55 km/s) velocity is correct, the most likely outcome is that it was a reverse-meteor, something that burned up going up through the atmosphere, not down. And even if it did have enough speed to get out of the atmosphere, and there was enough of it left, it most likely fell right back down through the atmosphere somewhere else, either burning up on re-entry or hitting the ground (or the water) somewhere else.

      • @druidjaidan@lemmy.world
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        27 months ago

        Ignoring that it burned up and ignoring losses due to drag if it somehow didn’t. Isn’t the point of escape velocity that it explicitly won’t come back down.iar least not on earth. Your trajectory won’t matter as you have enough velocity to escape the gravity of earth and will orbit the sun. Further if you managed the solar system escape velocity you will end up orbiting the galactic core. Trajectory doesn’t matter if you have escape velocity. Correct trajectory just minimizes the delta v needed to reach that escape velocity.

        At least that’s all my recollection.

        • @Maggoty@lemmy.world
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          27 months ago

          Escape velocity means you could stay in orbit. It doesn’t guarantee anything if you launch at the wrong angle.

          • @druidjaidan@lemmy.world
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            17 months ago

            That is not the definition of escape velocity. Escape velocity is the minimum velocity to escape a body’s gravity well entirely. Orbital is much lower

          • @merc@sh.itjust.works
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            27 months ago

            Exactly. It’s the minimum speed required to get into orbit assuming you get the direction correct. If you launch vertically, you’ll almost certainly come back down, no matter how far out into space you go. The only consideration is that if you go far enough out you might be influenced by the gravity of something else like the moon which could change your trajectory.

            • @druidjaidan@lemmy.world
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              27 months ago

              That is not the definition of escape velocity. Escape velocity is the minimum velocity to escape a body’s gravity well entirely. Orbital is much lower

      • @Swedneck@discuss.tchncs.de
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        17 months ago

        correction to your correction: it would not fall into the sun, falling into the sun is basically impossible, it would just end up in a highly eccentric orbit around the sun.

        • @merc@sh.itjust.works
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          17 months ago

          Yeah, “fall into the sun” was sort of hyperbole. If it truly got out into space and was going fast enough to escape Earth’s gravity, it would start orbiting with earth’s orbit plus some delta. Out of all the possible angles it could leave the earth, there are probably 2 angles where it would directly hit the sun One is the angle that cancels out all the orbital velocity of the earth and sends it directly at the sun, the other is the one that does the same but sends it directly away from the sun. Of all the possible trajectories on the surface of a sphere, only those two tiny solutions would end up with it contacting the sun, everything else would result in an orbit.

          Of course, given enough time, it’s pretty likely that if it isn’t collected by a planet, it will eventually end up in the sun. There isn’t much friction in space, but there’s a tiny bit: solar wind, micrometeoroids, etc. Eventually its orbit would decay and it would stray too close to the sun.

    • @CellarRat@sh.itjust.works
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      37 months ago

      I like how they are implying the speed of light is only 500000mph (as opposed to 671,000,000 mph or 1,080,000,000kph)

    • @Bosht@lemmy.world
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      278 months ago

      Gotta love Tumblr. Just massive amounts of disinformation and bullshit all the time.

    • @stephen01king@lemmy.zip
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      27 months ago

      94000mph is relative to the sun’s surface. Relative to the Earth’s surface, it is around 37000mph, which means they were still wrong.

    • @deadbeef79000@lemmy.nz
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      18 months ago

      If the event was near the equatorial near midday then there’s a very very (very) slim chance it was pointed directly at the sun.

      • atocci
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        148 months ago

        If it was pointed directly at the sun, it would miss. Not that this would make the odds any better, but aiming straight at the sun doesn’t work either.

    • @jballs@sh.itjust.works
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      178 months ago

      Saying this with only an understanding of orbital mechanics learned from Kerbal Space Program, I’d say the chances are damn near 0%. Hitting the sun is actually pretty difficult and requires a precise amount of Δv (change in velocity). This thing had such a huge Δv that it would have left the solar system.